Constitutive Relation

For a viscous material, the Cauchy stress tensor depends not only on the deformation gradient but also on its time derivative. That is

$\displaystyle \mathbf{T} = \mathbf{T}(\mathbf{F},\dot\mathbf{F}).$ (6.1.1)

Most fluids are isotropic and homogeneous; an exception being a liquid crystal which is anisotropic. Here we will study isotropic fluids only. For an isotropic fluid, equation (6.1.1) reduces to

$\displaystyle \mathbf{T} = \mathbf{T}(\rho, \mathbf{D}),$ (6.1.2)

and for a linear viscous fluid, we have

$\displaystyle \mathbf{T} = -p(\rho )\mathbf{1} + \lambda (tr\, \mathbf{D})\mathbf{1} + 2\mu\mathbf{D}.$ (6.1.3)

Here $ p$ is the hydrostatic pressure, $ \lambda$ the bulk viscosity and $ \mu$ the shear viscosity. The word linear in linear viscous fluid signifies that the viscous part of the stress (the last two terms on the right-hand side of (6.1.3)) depends linearly upon the strain-rate tensor $ \mathbf{D}$. A perfect fluid or an ideal gas has no viscosity, and therefore can be described by the constitutive relation

$\displaystyle \mathbf{T} = - p(\rho )\mathbf{1}.$ (6.1.4)

Thus a perfect fluid is a nonlinear elastic material in the sense that the Cauchy stress for it depends only on the present value of the deformation gradient. For an ideal gas,

$\displaystyle p = RT\rho$ (6.1.5)

where $ R$ is the universal gas constant and $ T$ is the temperature in degrees Kelvin. Thus for deformations of an ideal gas at a constant temperature

$\displaystyle \mathbf{T} =\ $   const.$\displaystyle \, \rho \mathbf{1}$ (6.1.6)

and the value of the const. depends upon the gas and its temperature.

Equation (6.1.3) for $ \mathbf{D} = \mathbf{0}$ gives

$\displaystyle \mathbf{T} = - p(\rho )\mathbf{1}.$ (6.1.7)

Hence in a fluid at rest, the state of stress is a hydrostatic pressure. Note that the state of stress in a perfect fluid or an ideal gas is always that of hydrostatic pressure whether or not it is being deformed. However, in a viscous fluid, no shear stress exists if and only if it is at rest. This is sometimes taken as the definition of a viscous fluid; viz. a viscous fluid at rest can not support any shear stresses. On the other hand, a solid body when subjected to shear or tangential tractions can stay stationary.

For a homogeneous fluid the viscosities $ \lambda$ and $ \mu$ are constants. Equation (6.1.3) implies that the principal axes of the stretching tensor or the strain-rate tensor $ \mathbf{D}$ coincide with the principal axes of the stress tensor $ \mathbf{T}$.

Whereas the constitutive relation (5.2.1) or (5.2.2) for a linear elastic material describes well its infinitesimal deformations, no such restriction is imposed on (6.1.3). Said differently, equation (6.1.3) describes deformations of a viscous fluid for all values of the stretching tensor $ \mathbf{D}$. The material characterized by equation (6.1.3) is called a Navier-Stokes fluid. Usually fluids and gases are assumed to be incompressible. The constitutive relations for an incompressible ideal gas and an incompressible Navier-Stokes fluid are respectively

$\displaystyle \mathbf{T} =\ $ $\displaystyle -p\mathbf{1},$ (6.1.8)
$\displaystyle \mathbf{T} =\ $ $\displaystyle -p\mathbf{1} + 2\mu \mathbf{D},$ (6.1.9)

where the hydrostatic pressure $ p$ is not determined by the deformation of the fluid. It is, however, determined by the boundary conditions. Even for a homogeneous fluid, the pressure $ p$ is a function of the spatial coordinate $ \mathbf{x}$ and time $ t$. In (6.1.9) we have used the continuity condition, $ tr\, \mathbf{D} = 0$, for an incompressible fluid.